C#双向链表的异常处理

在C#中实现双向链表的异常处理可以通过使用try-catch块来捕获异常。以下是一个简单的示例：

using System;

public class Node
{
    public T Data { get; set; }
    public Node Next { get; set; }
    public Node Prev { get; set; }

    public Node(T data)
    {
        Data = https://www.yisu.com/ask/data;>
{
    private Node head;
    private Node tail;

    public void Add(T data)
    {
        Node newNode = new Node(data);

        if (head == null)
        {
            head = newNode;
            tail = newNode;
        }
        else
        {
            tail.Next = newNode;
            newNode.Prev = tail;
            tail = newNode;
        }
    }

    public void Print()
    {
        Node current = head;
        while (current != null)
        {
            Console.Write(current.Data + " ");
            current = current.Next;
        }
        Console.WriteLine();
    }
}

class Program
{
    static void Main()
    {
        try
        {
            DoublyLinkedList list = new DoublyLinkedList();
            list.Add(1);
            list.Add(2);
            list.Add(3);
            list.Print();
        }
        catch (Exception ex)
        {
            Console.WriteLine("An error occurred: " + ex.Message);
        }
    }
}

在上面的示例中，我们将异常处理放在了Main方法中。当在添加节点时发生异常时，将捕获并打印出错误消息。您可以根据自己的需求添加更多的异常处理逻辑。