c# newtonsoft如何处理自定义数据类型

在C#中，使用Newtonsoft.Json库处理自定义数据类型非常简单。首先，确保已经安装了Newtonsoft.Json NuGet包。然后，按照以下步骤操作：

1. 定义自定义数据类型：

public class CustomDataType
{
    public int Id { get; set; }
    public string Name { get; set; }
    public AddressData Address { get; set; }
}

public class AddressData
{
    public string Street { get; set; }
    public string City { get; set; }
    public string State { get; set; }
    public string ZipCode { get; set; }
}

2. 在需要序列化或反序列化的类中，使用CustomDataType作为属性。例如：

public class Person
{
    public int Id { get; set; }
    public string Name { get; set; }
    public CustomDataType Address { get; set; }
}

3. 序列化对象：

using Newtonsoft.Json;

Person person = new Person
{
    Id = 1,
    Name = "John Doe",
    Address = new CustomDataType
    {
        Id = 100,
        Name = "123 Main St",
        Address = new AddressData
        {
            Street = "Main Street",
            City = "Anytown",
            State = "CA",
            ZipCode = "12345"
        }
    }
};

string json = JsonConvert.SerializeObject(person);
Console.WriteLine(json);

这将输出：

{
  "Id": 1,
  "Name": "John Doe",
  "Address": {
    "Id": 100,
    "Name": "123 Main St",
    "Address": {
      "Street": "Main Street",
      "City": "Anytown",
      "State": "CA",
      "ZipCode": "12345"
    }
  }
}

4. 反序列化对象：

string json = "{\"Id\":1,\"Name\":\"John Doe\",\"Address\":{\"Id\":100,\"Name\":\"123 Main St\",\"Address\":{\"Street\":\"Main Street\",\"City\":\"Anytown\",\"State\":\"CA\",\"ZipCode\":\"12345\"}}}";

Person person = JsonConvert.DeserializeObject(json);
Console.WriteLine($"Id: {person.Id}, Name: {person.Name}, Address: {person.Address.Name}, {person.Address.Address.Street}, {person.Address.Address.City}, {person.Address.Address.State}, {person.Address.Address.ZipCode}");

这将输出：

Id: 1, Name: John Doe, Address: 123 Main St, Main Street, Anytown, CA, 12345

通过这种方式，您可以使用Newtonsoft.Json库轻松地处理自定义数据类型。