在 JavaScript 中,可以在一个 switch
语句内部嵌套另一个 switch
语句。这种嵌套的使用技巧可以让你的代码更加模块化和易于维护。以下是一些建议和技巧:
-
将相关的逻辑放在一起:嵌套
switch
语句可以让你将与特定条件相关的逻辑组合在一起,使代码更易于阅读和理解。 -
使用有意义的命名:为每个
case
和嵌套的switch
语句提供有意义的名称,以便于理解代码的意图。 -
保持简洁:尽量避免过深的嵌套,以保持代码的可读性。如果嵌套层数过多,可以考虑将部分逻辑提取到函数中。
-
使用默认情况:在每个
case
和嵌套的switch
语句中添加默认情况,以处理可能未覆盖到的值。
下面是一个嵌套 switch
语句的示例:
function getDayOfWeek(dayNumber) { let dayOfWeek; switch (dayNumber) { case 0: dayOfWeek = 'Sunday'; break; case 1: dayOfWeek = 'Monday'; break; case 2: dayOfWeek = 'Tuesday'; break; case 3: dayOfWeek = 'Wednesday'; break; case 4: dayOfWeek = 'Thursday'; break; case 5: dayOfWeek = 'Friday'; break; case 6: dayOfWeek = 'Saturday'; break; default: dayOfWeek = 'Invalid day number'; } return dayOfWeek; } function getWeekInfo(weekNumber) { let weekInfo; switch (weekNumber) { case 1: weekInfo = 'Week 1'; break; case 2: weekInfo = 'Week 2'; break; case 3: weekInfo = 'Week 3'; break; case 4: weekInfo = 'Week 4'; break; default: weekInfo = 'Invalid week number'; } return weekInfo; } function getDayInfo(dayNumber, weekNumber) { const dayOfWeek = getDayOfWeek(dayNumber); const weekInfo = getWeekInfo(weekNumber); switch (dayOfWeek) { case 'Sunday': return `Today is ${dayOfWeek}, ${weekInfo}.`; case 'Monday': return `Today is ${dayOfWeek}, ${weekInfo}.`; case 'Tuesday': return `Today is ${dayOfWeek}, ${weekInfo}.`; case 'Wednesday': return `Today is ${dayOfWeek}, ${weekInfo}.`; case 'Thursday': return `Today is ${dayOfWeek}, ${weekInfo}.`; case 'Friday': return `Today is ${dayOfWeek}, ${weekInfo}.`; case 'Saturday': return `Today is ${dayOfWeek}, ${weekInfo}.`; default: return `Today is ${dayOfWeek}, ${weekInfo}.`; } } console.log(getDayInfo(3, 2)); // Output: Today is Wednesday, Week 2.
在这个示例中,我们使用了嵌套的 switch
语句来根据输入的星期几和周数获取对应的星期信息。这种结构使得代码更加模块化和易于维护。