如何通过PHP的json_encode实现数据格式转换

json_encode() 是 PHP 中用于将数组或对象转换为 JSON 格式的字符串的函数。以下是如何使用 json_encode() 实现数据格式转换的示例：

1. 将关联数组转换为 JSON 字符串：

 "John",
    "age" => 30,
    "city" => "New York"
);

$json_string = json_encode($assoc_array);

echo $json_string;
?>

输出：

{"name":"John","age":30,"city":"New York"}

2. 将多维数组转换为 JSON 字符串：

 "John",
        "age" => 30,
        "city" => "New York"
    ),
    array(
        "name" => "Jane",
        "age" => 28,
        "city" => "San Francisco"
    )
);

$json_string = json_encode($multi_dim_array);

echo $json_string;
?>

输出：

[
  {"name":"John","age":30,"city":"New York"},
  {"name":"Jane","age":28,"city":"San Francisco"}
]

3. 将对象转换为 JSON 字符串：

$name, $age, $city) {
        $this->name = $name;
        $this->age = $age;
        $this->city = $city;
    }
}

$person = new Person("John", 30, "New York");

$json_string = json_encode($person);

echo $json_string;
?>

输出：

{"name":"John","age":30,"city":"New York"}

注意：json_encode() 函数在处理特殊字符（如非 ASCII 字符）时可能会返回 null 或抛出警告。为了避免这些问题，可以使用 JSON_UNESCAPED_UNICODE 选项来保留 Unicode 字符：

输出：

{"name":"John","age":30,"city":"纽约"}